2017 FURTHERMATHEMATICS ANSWER

FURTHERMATHEMATICS NIGERIAN ANSWERS BY JOSH

1a)
g(x)=y
y=x+6
x=y-6
g^- f(x-6)
=4-5(x-6)/2=4-5x+30/2
=34-5x/2

1b)
coodinate=(x1+x2/2 ,y1+y2/2)
=(7-2/2,7-5/2)=(5/2,2/2)
=(5/2,1)

11a)Given:
f(x)={(4x-x^2)dx
f(x)=2x^2 - x^3/3 + K
f(3)=2(3)^2 - (3)^2/3  + K =21
18 - 9 + K=11
9+K=21
K=21-9
K=12
Therefore
f(x)= -x^3 + 2x^2 + 12

11b)Given
AP: T2=a+d
T4=a+3d
T8=a+7d
Since they form the consecutive numbers of a G.P.
a+3d/a+d=a+7d/a+3d
a^2+6ad+9d^2=a^2+8ad+7d^2
6ad+9d^2=8ad+7d^2
6a+9d=8a+7d
9d-7d=8a-6a
2d=2a
a=d------Eqn(1)

(14ai)
SKETCH THE DIAGRAM

14ii)
Using lami's theory
T1/sin60=T2/sin30
48N/sin60=T2/sin30
48N/0.8660=T2/0.5
0.5(48)/0.8660=T2(0.8660)/0.8660
T2=24/0.8660
T2=27.7N

(14b)
Using the equation of motion
H=U^2/2g
H=(20)^2/2*10
=20*20/20
H=20m
Timetaken to reach the maximum height
S=Ut+1/2at^2
20=0+1/2(100)t^2
20/5=5t^2/5
t^2=4
t=sqroot4
t=2S

TYPING


Whatsapp:07030121644